Jump to content

Dumbass Shit We See On Facebook


Vic Mackey

Recommended Posts

On 5/23/2021 at 3:41 PM, Vic Mackey said:
On 5/22/2021 at 11:57 PM, Txslnghrns said:
SIAPea62abb1156d5af0667dea10ab4bc554.jpg
I can get rid of 2 and 4 no problem. And with a heavy heart, Dr Pepper has to be the other. I don’t drink much soda. But when I do.....emoji22.png

Easy. 3, 4, 7. I already don't participate in any of that.

But has your A1C improved to acceptable levels?

Link to comment
Share on other sites

4 hours ago, Vic Mackey said:
A young lady committed a crime and she was sent to court. The punishment for the crime was life imprisonment. She shed tears for help but to no one available for help. When the case was called in court she started weeping.
Her family and friends who accompanied her started weeping but there was no hope. But something happened. Before the young lady could stand in the witness box a man stood up and the court room was silent. Everyone looked at Him. He was noble and gentle. He stood in the witness box and interceded on behalf of the woman.
The case was difficult, yet He used all His strength, energy and resources to fight on behalf of the woman. After a long legal battle between the man and the accusers, the lady was set free. The lady fell before the man and asked *'WHO ARE YOU'* The next day the lady deliberately committed another crime and was sent to the same court.
As soon as she entered the courtroom, she saw the man who interceded for her the previous day on the judgement seat. He was no longer a lawyer, but a judge. With smiles on her face the lady said *'I have come again'*
The man lifted his head and said 'yesterday I was a lawyer, so I fought for you, even when you were guilty. But today I am a judge and my judgement must be fair.' With tears in the ladies eyes she asked for the second time *'WHO ARE YOU'* and the man replied
*"YESTERDAY I WAS YOUR SAVIOUR. BUT NOW I AM YOUR JUDGE"*
Today Christ Jesus is our lawyer and redeemer, but a day is coming when He will give a fair judgement to everyone.
*JESUS IS COMING SOON, SO PREPARE TO MEET HIM*.
52355760_2089636907763190_22374349863261

I believe the title of this is "The Unfriending Story."

  • Haha 1
Link to comment
Share on other sites

24 minutes ago, tbone_ said:

As soon as he left the diving board he would start to move forward slower than the truck.

Yes, and if you knew the air density, cross sectional area of the man, drag coefficient of the man, and the velocity of the rv you could calculate how much he would slow down in the approximately 1 second it took him to jump up and come down.  I think you would find that the change in velocity was not really that significant. The force in Newton’s acting to slow him down would be equal to the air density times the drag coefficient times the cross sectional area divided by 2 times the velocity squared.  You take the calculated force in Newton’s acting on the man from air resistance and put it in the formula F=m*(v/t) where m is the mass of the man and t is the time it takes him to jump up and down and solve for v.  That should give you the change in velocity of the man.  Multiply the change in velocity time the time it takes him to jump up and come down and you then have the distance he fell behind.

Edited by NeverMarryAStripper
  • Hook 'Em 4
  • Like 3
  • Rage+1 1
Link to comment
Share on other sites

31 minutes ago, NeverMarryAStripper said:

Yes, and if you knew the air density, cross sectional area of the man, drag coefficient of the man, and the velocity of the rv you could calculate how much he would slow down in the approximately 1 second it took him to jump up and come down.  I think you would find that the change in velocity was not really that significant. The force in Newton’s acting to slow him down would be equal to the air density times the drag coefficient times the cross sectional area divided by 2 times the velocity squared.  You take the calculated force in Newton’s acting on the man from air resistance and put it in the formula F=m*(v/t) where m is the mass of the man and t is the time it takes him to jump up and down and solve for v.  That should give you the change in velocity of the man.  Multiply the change in velocity time the time it takes him to jump up and come down and you then have the distance he fell behind.

I was told there would be no math

  • Hook 'Em 1
  • Like 1
Link to comment
Share on other sites

1 hour ago, NeverMarryAStripper said:

Yes, and if you knew the air density, cross sectional area of the man, drag coefficient of the man, and the velocity of the rv you could calculate how much he would slow down in the approximately 1 second it took him to jump up and come down.  I think you would find that the change in velocity was not really that significant. The force in Newton’s acting to slow him down would be equal to the air density times the drag coefficient times the cross sectional area divided by 2 times the velocity squared.  You take the calculated force in Newton’s acting on the man from air resistance and put it in the formula F=m*(v/t) where m is the mass of the man and t is the time it takes him to jump up and down and solve for v.  That should give you the change in velocity of the man.  Multiply the change in velocity time the time it takes him to jump up and come down and you then have the distance he fell behind.

Newtons.  ffs. 

Link to comment
Share on other sites

12 hours ago, NeverMarryAStripper said:

Yes, and if you knew the air density, cross sectional area of the man, drag coefficient of the man, and the velocity of the rv you could calculate how much he would slow down in the approximately 1 second it took him to jump up and come down.  I think you would find that the change in velocity was not really that significant. The force in Newton’s acting to slow him down would be equal to the air density times the drag coefficient times the cross sectional area divided by 2 times the velocity squared.  You take the calculated force in Newton’s acting on the man from air resistance and put it in the formula F=m*(v/t) where m is the mass of the man and t is the time it takes him to jump up and down and solve for v.  That should give you the change in velocity of the man.  Multiply the change in velocity time the time it takes him to jump up and come down and you then have the distance he fell behind.

Are you suggesting coconuts migrate?

  • Hook 'Em 1
  • Like 2
Link to comment
Share on other sites

Yes, and if you knew the air density, cross sectional area of the man, drag coefficient of the man, and the velocity of the rv you could calculate how much he would slow down in the approximately 1 second it took him to jump up and come down.  I think you would find that the change in velocity was not really that significant. The force in Newton’s acting to slow him down would be equal to the air density times the drag coefficient times the cross sectional area divided by 2 times the velocity squared.

What if he’s going as fast as an unladen swallow?
  • Like 2
Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.



×
×
  • Create New...